Chemistry, 16.10.2021 01:30, netflixacc0107
How many moles of AlCl3 (133.34 g/mol) are needed to produce 258 g of Cl2 (70.91 g/mol)? 4 AlCl3(s) + 3 O2(g) → 2 Al2O3(s) + 6 Cl2(g)
Answers: 3
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How many moles of AlCl3 (133.34 g/mol) are needed to produce 258 g of Cl2 (70.91 g/mol)?
4 AlCl3(s...
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