To study a marine organism, a biologist prepares a 1.00-kgsample to simulate the ion concentrations in seawater. She mixes 26.5 g of NaCl, 2.40 g of MgCl₂, 3.35 g of MgSO₄, 1.20 g of CaCl₂, 1.05 g of KCl, 0.315 g of NaHCO₃, and 0.098 g of NaBr in distilled water. (a) If the density of the solution is 1.025 g/cm³,what is the molarity of each ion? (b) What is the total molarity of alkali metal ions? (c) What is the total molarity of alkaline earthmetal ions? (d) What is the total molarity of anions?

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.