Calculate ΔH for the following reaction: PCl3 (l) + Cl2 (g) → PCl5 (s)

given the following:

1) 2 P (s) + 3 Cl2 (g) → 2 PCl3 (l) ΔH = -639.4 kJ

2) 2 P (s) + 5 Cl2 (g) → 2 PCl5 (s) ΔH = -887.0 kJ

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

a compound is a molecule made of atoms from different elements.

a. by the combination of an unlimited number of elements

you didnt put any of the following

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2