What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCl? O A. 3.5 mol/L
O B. 150 mol/L
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O C. 3.3 mol/L
O D. 3.5 x 10-3 mol/L

3.5 mol/L

Explanation:

First convert the 139.9g of LiCl into moles of LiCl.  Don't do the sig fig rule until the very end.

Second, take 930mL of LiCl and divide it by 1000 to convert it to liters.

Third use the molarity formula which is M=mol/L and divide 0.930L by 3.300773877mol and you will get 3.549219223.  This is where the sig fig rule will come into play.  3.5mol/L is a reasonable answer for this problem.