Equal volumes of carbon (II) oxide and carbon (IV) oxide are allowed to diffuse through the same medium. Calculate the relative rate of diffusion of carbon (II) oxide. (C = 12,0 = 16) (3 marks)

h let me think

answer; i believe the correct answer is (solid gold);

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.

hcl + naoh → h2o + nacl

explanation:

hcl + naoh → h2o + nacl   is the reaction that is correctly balanced.

however, pcl3 + h2 → ph3 +3hcl, 2ca+ 3cl2 → cacl3, and c5h12 + 5o2 → 5co2 + 6h2o are not correctly balanced.