Calculate the mass in grams of NaOH required to make up a 1.57 M aqueous solution in a 25.0 mL volumetric flask.
The molar mass of NaOH is 40.0 g/mol.
Give your answer to three significant figures.

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1) mass= M×V(L)×molar mass

Mass=1.57 × 0.025×40.0

= 1.57 g

2) M1V1 = M2V2

0.80×31.5=50.0 × M

M = 0.540 M

3) M1V1 = M2V2

1.10 × V= 0.0275×1000

V = 25.0 mL

the answer is symmetrical : )