(BRAINLIEST) For a reaction:
Ca(OH)₂ + 2NH₂Cl → CaCl₂ + 2NH₂ + 2H₂O

The reaction is carried out by mixing 7 g of pure (Ca(OH)₂ and 7 g of pure NHCI

(a) Find the limiting reactant.
(b) Calculate the mole of unreacted reactant left over.
(c) How many grams of CaCl, are formed? (d) What volume of NH, gas are produced at 27°C and 1.5 atmospheric pressure?

Ca(OH)₂ + 2NH₂Cl → CaCl₂ + 2NH₂ + 2H₂O

Explanation:

here is it

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied