-16 9. What wavelength (~) of radiation has photons of energy (E) at 2.87 x 10^-16 J?

10. A photon of visible light has a frequency (v) of 4.3 x 10^14 s^-1. What is the energy (E) of this photon?

11. Calculate the energy(E) of a photon of radiation whose wavelength() is 322nm.
Note: (1nm=1x10-9-m)

12. What wavelength(2) of radiation has photons of energy (E) at 2.87 x 10^-16 J?

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.