Temp (K) k
279.1 0.0053
289.8 0.0071
298.6 0.0092
300.2 0.0092
314 0.013Gi...
Chemistry, 01.10.2021 01:30, ladypink94
Temp (K) k
279.1 0.0053
289.8 0.0071
298.6 0.0092
300.2 0.0092
314 0.013Given the information in the table above find the activation energy in kJ/mol:
Round all answer to 2 decimal places"
Answers: 2
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Use the periodic table to complete this equation that represents nuclear fission processesun - ba c 3 n
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