Chemistry, 29.09.2021 20:10, mucciak2854
A pure titanium cube has an edge length of 2.63 in. How many titanium atoms does it contain? Titanium has a density of 4.50g/cm3. I messed something up along the line and would appreciate it if someone could tell me what I did wrong and how to solve it correctly.
V = 2.63^3 = 18.19in^3
1in^3 = 16.387cm^3
18.19/16.387 = 1.1539
Density = 4.50g/cm^3
1.1539 * 4.50 = 5.1926
1mol Ti = g/47.867
5.1926/47.867 = 0.108479
1mol = 6.02 * 10^23atoms
0.108479/(6.02 * 10^23) = 6.53 * 10^22
This is wrong. Why!?
Answers: 1
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A pure titanium cube has an edge length of 2.63 in. How many titanium atoms does it contain? Titaniu...
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