How many moles of lead would have been melted, if you lost 13,000 J of energy? (Heat of fusion = 162 J/g)

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: i hope this . =)

Answerstudying coal cumbustion as an energy source;

Elements would be the right answer

Acidichope this