3. Beaker A (Heat Meter) tells us how much heat energy left the hot plate and entered into Experiment Beaker C. One calorie of energy
is the amount of heat required to increase the temperature of 1 ml
of water 1°C. How much did the temperature change in Beaker A?
°C. (Subtract the starting temperature if it was above 0°C.)
4. Now, calculate the total calories of heat recorded by the Heat Meter
(Beaker A) considering both the amount of water in it and the
temperature change of the water.
calories
5. The answer to question #4 is the amount of energy to vaporize 10 ml
of water in Beaker C. How many calories would be required to
evaporate only 1 ml of water?
calories
6. Based on your results, discuss how effective is the evaporation of
water at removing excess heat from your body (sweating).
L

In a laboratory experiment, a fermenting aqueous solution of glucose and yeast produces carbon dioxide gas and ethanol. the solution was heated by burning natural gas in a bunsen burner to distill the ethanol that formed in the flask. during the distillation, the ethanol evaporated and then condensed in the receiving flask. the flame of the burner was kept too close to the bottom of the flask and some of the glucose decomposed into a black carbon deposit on the inside of the flask. during this experiment the following changes occurred. which of these changes involved a physical change and not a chemical change? check all that apply. 1-condensation of ethanol 2-evaporation of ethanol 3- formation of carbon dioxide gas from glucose burning of natural gas 4-formation of ethanol from glucose by yeast 5-formation of a carbon deposit inside the flask

Butadiene undergoes a reaction at a certain temperature in the gas phase as follows: 2c4h6(g) --> c8h12(g) the following data were collected for this reaction: time (min) [c4h6] (m) 0 0.36 15 0.30 30 0.25 48 0.19 75 0. determine the order of the reaction and the rate constant. 1st order and k = 4.3x10 -4 s-1 1st order and k = 2.3x10-4 s-1 2nd order and k = 4.3x10-4 s-1 2nd order and k = 2.3x10-4 s-1 zero and k = 4.3x10-4 s-1

Calculate the molarity of 48.0 ml of 6.00 m h2so4 diluted to 0.250 l .