Two groups of students were given one white mineral sample to identify. Each group first determined the density of the sample to be 2.7 g/cm". The groups had additional tests available to
them to help with identification. One group identified the sample as calcite. The other group identified the sample as plagioclase feldspar. Which of these statements BEST explains the
difference in the conclusions of the two groups of students?
One group recerved a different sized sample
One group had more students perform the tests
One group ade an error in the density calculation
One group performed more types of tests on the sample
Answers: 3
Chemistry, 22.06.2019 02:30, ulilliareinhart2
The is a particle with one unit of positive charge a. proton b. positron c. electron d. nucleus awnser quick it is a important science test!
Answers: 2
Chemistry, 22.06.2019 20:00, aksambo4707
Many free radicals combine to form molecules that do not contain any unpaired electrons. the driving force for the radical–radical combination reaction is the formation of a new electron‑pair bond. consider the chemical equation. n(g)+no(g)⟶nno(g) n(g)+no(g)⟶nno(g) write lewis formulas for the reactant and product species in the chemical equation. include nonbonding electrons. n(g)n(g) select draw rings more erase select draw rings more erase select draw rings more erase n no(g)
Answers: 1
Chemistry, 22.06.2019 23:00, ceejay8005
The data below were determined for the reaction shown below. s2o82– + 3i – (aq) → 2so42– + i3– expt. # [s2o82–] (m) [i –] (m) initial rate 1 0.038 0.060 1.4 × 10 – 5 m/s 2 0.076 0.060 2.8 × 10 – 5 m/s 3 0.076 0.030 1.4 × 10 – 5 m/s the rate law for this reaction must be:
Answers: 1
Two groups of students were given one white mineral sample to identify. Each group first determined...
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