Use the equation to complete the activity. 219 86Rn→215 84Po+α
The nuclear equation shows the transmutation of a form of radon into polonium and an alpha particle. In one to two sentences, explain whether or not the reaction is balanced.

(2 points)

The most important thing to know is that an α-particle (alpha particle) is a helium nucleus.

Explanation:

It contains 2 protons and 2 neutrons, for a mass number of 4.

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.

Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:

226

88

Ra

→

222

86

Rn

+

4

2

He

Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation. Also, the sum of the superscripts (masses) is the same on each side of the equation.

EXAMPLE

Write a balanced nuclear equation for the α decay of polonium-208.

Solution

The unbalanced equation is

208

84

Po

→

4

2

He

+

X

The superscript of

X

must be 208 – 4 = 204.

The subscript of

X

must be 84 – 2 = 82.

Element 82 is Pb. So the equation is

208

84

Po

→

4

2

He

+

204

82

Pb

Explanation:hope this is right and helps

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explanation: