How many moles of hcl are required to completely neutralize 0.30 moles of ca(oh)2?

a) 0.30 moles
b) 0.60 moles
c) 0.15 moles
d) 1.0 mole

 If i'm not mistaken the ratio is between Ca(OH)2 and HCl in the balanced equation 

Ca(OH)2 + 2 HCl = CaCl2 + 2 H2O 

is 1 : 2 

moles HCl required = 0.30 x 2 = 0.60

So, the answer should be: B) 0.60 moles

♦Brainliest Please♦

Sorry i dont understand the question can you rephase it?