5. The standard enthalpy change of three combustion reactions is given below in kJ. 2C2H6(g) + 702(g) → 4CO2(g) + 6H2O(1) AH =-3120 2H2(g) + O2(g) → 2H2O(1) AHO=-572 C2H4(g) + 302(g) → 2CO2(g) + 2H2O(1) AHO=-1411 Based on the above information, calculate the standard change in enthalpy, AHO, for the following reaction. C2H6(g) - C2H4(g) + H2(g)​

10 years is the answer

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally