EXPERIMENTAL DESIGN DIAGRAM 1) Rend the following experimental scenario and fill out the Experimental Design Diagram Below for
the experiment described below.
METALS AND RUSTING TRON: In chemistry class, Allen determined the effectiveness of various
metals in releasing hydrogen gas from hydrochloric acid. Several weeks later, Allen read that a utilities
company was burying lead next to iron pipes to prevent rusting. Allen hypothesized that less rusting
would occur with the more active
metals. He placed the following into four separate beakers of water:
(A) I iron nail, (B) 1 iron nail wrapped with an aluminum strip. (C) I iron nail wrapped with a
magnesium strip.(D) iron nail wrapped with a lead strip.
He used the same amount of water, equal amounts (mass) of metals, and the same type of iron nails. At
the end of 5 days, he rated the amount of rusting as small
, moderate or large. He also recorded the color
of the water
EXPERIMENTAL DESIGN DIAGRAM
Title:
Problem Statement:
Hypothesis:
Manipulated (Independent)
Variable
Number of Tests
Responding (Dependent)
Variable
Control Test
Controlled Variables

Help pls

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.