A sample of 29.344 g of dinitrogen monoxide reacts with an excess of oxygen to form 61.343 g of dinitrogen tetroxide. According to the Law of Conservation of Mass, the amount of oxygen gas that reacted with the nitrogen-containing gas is:
90.687 g O, 2
47.997 g O2
47.997 g O, 2
31.999 g O, 2
2.090 g O, 2
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