Consider equal mole samples of dinitrogen monoxide, aluminum nitrate, and potassium cyanide. Arrange these compounds in increasing order of number of nitrogen atoms in each sample. a. aluminum nitrate
b. potassium cyanide
c. dinitrogen monoxide

I think the answer will be C

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj