Be sure to answer all parts. The species CO, CN−, and C22− are isoelectronic. Determine the MO diagrams (assume 2s−2p mixing, as in N2), and determine the bond order that the species share. (σ2s)2(σ2s)2(π2p)2(π*2p)2(σ*2p)2 (σ2s)2(σ*2s)2(π2p)2(π2p)2(σ*2p)2 (σ2s)2(σ2s)2(π2p)2(π*2p)2(σ2p)2 (σ2s)2(σ*2s)2(π2p)2(π2p)2(σ2p)2 (σ2s)2(σ*2s)2(π2p)2(π*2p)2(σ2p)2 Bond order =

answer: mercury

explanation:

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72