A student titrated a solution containing 3.7066 g of an unknown Diprotic acid to the end point using 28.94 ml of 0.3021 M KOH solution. What is the molar mass of the unknown acid? Hint: you must write a balanced equation for the reaction.

Molar mass of the diprotic acid is 424 grams

Explanation:

[hint: diprotic acid only contains 2 hydrogen protons]

Ionic equation:

first, we get moles of potassium hydroxide in 28.94 ml :

since mole ratio of diprotic acid : base is 2 : 2, moles are the same.

Therefore, moles of acid that reacted are 0.008743 moles.

for the molar mass:

it should be p1 v1 = p2 v2