Chemistry, 18.08.2021 06:00, leilaford2003

Calculate the liters of a 4.40 M KCl solution to obtain 0.200 mole of KCI

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answered: rasv3491

$\boxed {\boxed {\sf 0.0455 \ L}}$

Explanation:

We are asked to calculate the liters given the molarity and moles in a solution.

Molarity is a measure of concentration in moles per liter. It is calculated with the following solution:

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

The molarity of the solution is 4.40 molar of potassium chloride (KCl). 1 molar is equal to 1 mole per liter, so the molarity is also 4.40 moles of potassium chloride per liter. There are 0.200 moles of potassium chloride or solute. The liters of solution is unknown, so we can use the variable x.

molarity= 4.40 moles KCl / L moles of solute = 0.200 mol KCl liters of solution = x

$4.40 \ mol \ KCl/ L = \frac{ 0.200 \ mol \ KCl}{x}$

Since we are solving for x, we must isolate the variable. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

$\frac {4.40 \ mol \ KCl/ L}{1} = \frac{ 0.200 \ mol \ KCl}{x}$

$4.40 \ mol \ KCl / L * x= 1 * 0.200 \ mol \ KCl$

$4.40 \ mol \ KCl / L * x= 0.200 \ mol \ KCl$

x is being multiplied by 4.40 moles of potassium chloride per liter. The inverse operation of multiplication is division. Divide both sides by 4.40 mol KCl/L

$\frac {4.40 \ mol \ KCl / L * x}{4.40 \ mol \ KCl / L}= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}$

$x= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}$

The units of moles of potassium chloride cancel.

$x= \frac {0.200}{{4.40 L}}$

$x= 0.0454545454545 \ L$

The original measurements of liters and moles have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ten-thousandth place (0.0454545454545). The 5 to the right of this place (0.0454545454545) tells us to round the 4 up to a 5.

$x \approx 0.455 \ L$

There are approximately 0.455 liters in a 4.40 molar solution with 0.200 moles of solute.

answered: Guest

it's all four options.

answered: Guest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

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Calculate the liters of a 4.40 M KCl solution to obtain 0.200 mole of KCI...