If 16.0 g of methane is allowed to react with 32.0 g of oxygen, what is the limiting reactant? Explain.
CH4(g) + 202 (g)
CO2 (g) + 2H2O(g)

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a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.