Chemistry, 09.08.2021 20:40, amcdonald009

2 C2H6(9) + 7 02(9) -> 4CO2(g) + 6 H20(9) K = 7.28x106 + Write the equilibrium value for the above reaction if the mole concentrations are doubled and the reactions is reversed.

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2 C2H6(9) + 7 02(9) -> 4CO2(g) + 6 H20(9) K = 7.28x106 + Write the equilibrium value for the abov...

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2 C2H6(9) + 7 02(9) -> 4CO2(g) + 6 H20(9) K = 7.28x106 + Write the equilibrium value for the above reaction if the mole concentrations are doubled and the reactions is reversed.​

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2 C2H6(9) + 7 02(9) -> 4CO2(g) + 6 H20(9) K = 7.28x106 + Write the equilibrium value for the above reaction if the mole concentrations are doubled and the reactions is reversed.