Calculate the mass of naphthalene required to react stoichiometrically with the moles of 2-bromo-2-methylpropane that you have placed in the flask. Dispense that quantity of naphthalene into the weighing dish. There is some imprecision in delivering the powder onto the weigh boat, but a mass within 0.040 g of the calculated stoichiometric quantity will be sufficient for this experiment. Note that you can use a combination of the 1 g and the 0.1 g buttons to add the required mass. If you overshoot the goal, you can discard the weighing boat and get a new one. RECord the sample mass dispensed below. mass of naphthalene (g)

The reaction of 2-bromo-2-methylpropane and naphthalene is stoichiometrically  in a mole ratio of 1:1.

Notice that in the question, the moles of 2-bromo-2-methylpropane placed in th flask wasn't mentioned. if I assume that it was 1.24 moles then;

1 mole of naphthalene reacts with 1 mole of 2-bromo-2-methylpropane

x moles of naphthalene reacts with 1.24 mole of 2-bromo-2-methylpropane

x = 1 * 1.24/1

= 1.24 moles of naphthalene

Molar mass of naphthalene  = 128.2 g/mol

Mass of naphthalene  = 128.2 g/mol * 1.24 moles of naphthalene

Mass of naphthalene  =159 g

For more about how to solve stoichiometry problems:

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence