Chemistry, 02.08.2021 14:00, omriejs5

Cho các quá trình và số liệu sau: C(d, s) ⭢ C (g, s) (1) : ΔH0298 = - 1,9 kJ
ΔG0298 = - 2,87 kJ
C(g, s) + O2 (k) ⭢ CO2 (k) (2): ΔH0298 = - 393,5 kJ
a)Giải thích tại sao trạng thái chuẩn của C lại là C(g) mà không phải là C (d).
b)Tính ΔH0298 của phản ứng sau:
C(d, s) + O2 (k) ⭢ CO2 (k) (3)
ΔH0298 của phản ứng 3 có phải là ΔH0298, sinh nhiệt của CO2 không ? Tại sao?

Answers: 2

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Cho các quá trình và số liệu sau: C(d, s) ⭢ C (g, s) (1) : ΔH0298 = - 1,9 kJ
ΔG0298 = - 2,87...