4 pts Question 5
Directions:
Solve the following problem on a separate sheet of paper.
Submit a photo (or scan) to receive credit. File type must be .pdf.
Problem:
Consider the balanced reaction: 4Ga(s) + 302(g) → 2Ga2O3(s)
When gallium metal reacts with 13.0 g of oxygen gas how many grams of gallium oxide will be
produced?
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First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

Cross multiply and solve for x:

4x=1.89

x=47 molesO₂

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

m=9

step-by-step explanation:

it takes on an electronical energy