Question 10 of 30 What is the change in the freezing point of water when 35.0 g of sucrose is
dissolved in 300.0 g of water?
Ktof water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
i value of sugar = 1
A. 0.0606 °C
B. 0.217°C
C. -0.183°C
D. -0.634°C
SUBMIT

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the answer is a. co2, this would be colder than the : )

explanation: