By using the following reactions, calculate the heat of combustion of pentane: C5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O (l).

C (s) + O2 (g) → CO2 (g), ΔH = –395 kJ
H2 (g) + 1/2O2 (g) → H2O (l), ΔH = –285 kJ
5C (s) + 6H2 (g) → C5H12 (g), ΔH = –147 kJ

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the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

explanation:

0.07 g/cm³

1.37 g/cm³