If a tank has a pressure of 135.0 kPa, a volume of 40.0 L, and is held at 30.0 degree Celcius, what would be the number of moles of gas is muxture is 20% gas A and 80% gas B?

It conforms what ever surface its in.

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m

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