How many grams of calcium chloride are needed to produce 10.0 g of potassium chloride? CaCl2(aq) + K2CO3(aq) → 2 KCl(aq) + CaCO3(aq)

11.1g

Explanation:

since the equation is already balanced just drop down the elements you will work with and use the mole to mole ratios

Cacl2 : 2Kcl

1 : 2

since potassium chloride has alot of information find it's moles

number of moles=mass/molecular mass

=10g/74.5

=0.13g/mol

now use the mole to mole ratios to find the number of moles of calcium chloride

1 : 2

x:0.13

2x/2=0.13/2

x=0.067g/mol of cacl2

then you can calculate the mass of calcium chloride

m=n×mm

=0.067×111

=7.4g

I hope this helps

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> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.