Wet helium gas is placed into a balloon at 24.4 degrees Celsius and a pressure of 765.3 mm Hg. What volume (in L) does the dry gas occupy if the water vapor pressure is 24.3 torr and the mass of dried helium gas in the balloon is 0.498 g

Hence the Volume of Gas = 3.04 L.

Explanation:  

pressure of dry gas = 765.3 - 24.3 = 741 mmhg  

Temperature of gas = 24.4+273.15 = 297.55 k  

No of mol of gas = 0.498/4 = 0.1245 mol  

R = gas constant = 0.0821 l.atm.k-1.mol-1  

From ideal-gas equation

PV = nRT  

(741/760) x v = 0.1245 x 0.0821 x 297.55  

V = Volume of Gas = 3.04 L

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.