Phản ứng 2NO2 thành N2O4 có hằng số cân bằng Kp =9. Ở cùng nhiệt độ, phản ứng sẽ diễn ra theo chiều nào khi áp suất riêng phần của N2O4 và NO2 lần lượt là 0,9 atm và 0,1 atm

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol