According to the ideal gas law, a 9.998 mol sample of argon gas in a 0.8311 L container at 502.7 K should exert a pressure of 496.2 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Ar
gas, a = 1.345 L’atm/mol? and b = 3.219x10-2 L/mol.
Pideal – Puan der Waals |
Percent difference
x 100

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set up the van der Waals' equation as shown below:

Thus, we secondly calculate the molar volume as:

Then, we plug in the entire variables in the vdW equation to get such pressure:

And the ideal gas pressure:

Finally, the percent difference:

Regards!

they are all solids.

the right answer is c i just did the question.