Mercury(II) sulfide is insoluble in pure water, but is soluble in a solution of sodium sulfide because: Select the correct answer below: Hg2 can form a complex with sulfide ions Na can form a complex with sulfide ions the excess of sulfide ions pushes the equilibrium toward further dissolution of HgS none of the above

Hg2 can form a complex with sulfide ions

Explanation:

The answer to this question is option a. Hg2+ can form a complex with sulfide ions

Whenever there is a chemical reaction between insoluble mercuric sulfide HgS and sodium sulfide Na2S aqueous solution, the results of this reaction is a soluble complex of mercury. that is, it forms sodium disulphidemercurate(ii).

The chemical reaction can be seen below

Hg(s) + Na2S > Na[HgS2](aq)

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.