Can anyone help me in my chemistry homework?​

what is in your chemistry home work I can try for...

1: A substance made by mixing other substances together.

2: Solutions, Suspensions, Colloids and Emulsion.

3: A particular kind of matter with uniform properties.

4: A homogenous mixture is that mixture in which the components mix with each other and its composition is uniform throughout the solution. A heterogenous mixture is that mixture in which the composition is not uniform throughout and different components are observed.

5: A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm. Common examples of solutions are the sugar in water and salt in water solutions, soda water, etc. In a solution, all the components appear as a single phase.

6: A solution forms when one substance dissolves in another. The substance that dissolves is called the solute. The substance that dissolves it is called the solvent. For example, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

7: Common examples of suspension include the mixture of chalk and water, muddy water, the mixture of flour and water, a mixture of dust particles and air, fog, milk of magnesia, etc. Q2. Give the definition of suspension. Ans: A suspension is a heterogeneous mixture of two or more substances.

8: The Tyndall effect is light scattering by particles in a colloid or in a very fine suspension.

Explanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.