How many grams of S206 are in 17.7 moles of S206?

2721.02 g

Explanation:

you need the molar mass of the compound to solve this

S2O6's molar mass: 2(S) + 6(O)

Sulfur (S) molar mass: 32.06

Oxygen (O) molar mass: 15.99

2(32.06) + 6(15.99) --> 64.12 + 95.94 = 160.06 g/mol

We want to know how much of it is in 17.7 moles, so you perform the following stoichiometry

160.06 g/mol * 17.7 mol

mol units cancel out and we are left with g.

160.06 * 17.7 = 2721.02 g of S2O6 in 17.7 moles of it

 The correct answer is 2721.02 g

it would be d. henry moseley

hope this !

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