If I have 9.7 moles of gas at a pressure of 0.12 atm and at a temperature of 46°C, what is the volume of the container that the gas is in?

2117.02 litres

Explanation:

Using the ideal gas equation as follows;

PV = nRT

Where:

P = pressure of the gas (atm)

V = volume of the gas (L)

n = number of moles (mol)

R = gas law constant (Latm/molK)

T = temperature (K)

According to the information given in this question,

P = 0.12 atm

V = ?

n = 9.7moles

T = 46°C = 46 + 273 = 319K

R = 0.0821 Latm/molK

Using PV = nRT

0.12 × V = 9.7 × 0.0821 × 319

0.12V = 254.04

V = 254.04 ÷ 0.12

V = 2117.02 litres

a