300.0 mL of a 0.335 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

The new concentration of the solution is 0.143 M.

Explanation:

Given: = 300.0 mL,     = 0.335 M

= 700.0 mL,         = ?

Formula used is as follows.

Substitute values into the above formula as follows.

Thus, we can conclude that the new concentration of the solution is 0.143 M.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

answermeridional ;