Na3N decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced how many moles of Na3N was used? (22.4 L = 1 mole of any gas)
2Na3N --> 6Na + N2

1.224 moles of were used.

Explanation:

We are given:

Volume of nitrogen gas produced = 13.7 L

At STP conditions:

22.4 L of volume is occupied by 1 mole of a gas

Applying unitary method:

13.7 L of nitrogen gas will be occupied by =

For the given chemical reaction:

By Stoichiometry of the reaction:

1 mole of nitrogen gas is produced by 2 mole of

So, 0.612 moles of nitrogen gas will be produced from = of

Hence, 1.224 moles of were used.

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the answer is:  

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