Chemistry, 29.06.2021 06:30, kimmmmmmy333

Exactly 75.00 mL of a 333.3 ppm (w/v) sodium sulfite (MM=126.041 g/mol), solution is treated with 150.0 mL of 3.894x10^-3 M perchloric acid (MM= 100.457 g/mol), which results in the formation of sulfur dioxide (MM=64.064 g/mol), water (MM=18.015 g/mol), and sodium perchlorate (MM=122.438 g/mol). What is the ppm (w/v) of the excess reactant once the reaction is complete?

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Exactly 75.00 mL of a 333.3 ppm (w/v) sodium sulfite (MM=126.041 g/mol), solution is treated with 15...