Please answer ASAP!! Cu+2 + 2e- ———> Cu E*= 0.52 V
Ag+1 + 1e- ———> Ag E*= 0.80 V

Using the two cell reduction potential shown for the corresponding reaction calculate the cell potential for a voltaic cell made from these two metals.
A. 1.32 V
B. -0.28 V
C.0.28 V
D. -1.32 V

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

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