An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the molality of the solution.

The molality of solution is 0.782 m

Explanation:

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

.....(1)

Given values:

Moles of = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

Hence, the molality of solution is 0.782 m

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