How many moles of CO2 exert a pressure of 2.34atm at a volume of 25.6L and a temperature of 305k?

2.39 moles

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 2.34 atm

Volume (V) = 25.6 L

Temperature (T) = 305 K

Number of mole (n) =?

NOTE: Gas constant (R) = 0.0821 atm.L/Kmol

The number of mole of CO₂ can be obtained by using the ideal gas equation as shown below:

PV = nRT

2.34 × 25.6 = n × 0.0821 × 305

59.904 = n × 25.0405

Divide both side by 25.0405

n = 59.904 / 25.0405

n = 2.39 moles

Thus, the number of mole of CO₂ is 2.39 moles.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o