When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

The % yield of the product is 87.05 %

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

......(1)

We are given:

Given mass of = 80 g

Molar mass of = 100 g/mol

Putting values in equation 1, we get:

For the given chemical reaction:

By stoichiometry of the reaction:

If 1 mole of produces 1 mole of CaO

So, 0.8 moles of will produce = of CaO

We know, molar mass of = 56 g/mol

Putting values in above equation, we get:

The percent yield of a reaction is calculated by using an equation:

......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

Hence, the % yield of the product is 87.05 %

answer: mole of the gas

answer: mole of the gasexplanation:

c. orbital shape i hope this is correct