. How many moles of BaSO4 could be obtained from 0.75moles of BaCl2 via the precipitation reaction: BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s) ?​

0.75 moles of BaSO4

Explanation:

Based on the balanced equation:

BaCl2(aq) + Na2S04(aq) --> 2NaCl(aq) + BaSO4(s)

1 mole of BaSO4 is obtained from 1 mole of BaCl2 when Na2SO4 is in excess.

That means if you add 0.75 moles of BaCl2, the moles of BaSO4 that could be obtained are the same:

0.75 moles of BaSO4

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