A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mixture is burned, it produces 780 kJ of heat. What is the mole fraction of methane in the mixture

Explanation:

From the question we are told that:

Pressure

Temperature

Volume

Heat Produced

Generally the equation for ideal gas is mathematically given by

Therefore

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

Comparing Equation 1 and 2 and solving simultaneously

Therefore

Mole fraction 0f Methane is mathematically given as

where's the diagram?