A 250ml sample of sir at 373.15k is warmed at 473.15 at constant pressure. What is the volume of the air sample at the new temperature

317 mL.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial temperature (T₁) = 373.15 K

Final temperature (T₂) = 473.15 K

Pressure = Constant

Final volume (V₂) =?

The final volume of the air sample can be obtained by using the Charles' law equation as illustrated below:

V₁/T₁ = V₂/T₂

250 / 373.15 = V₂ / 473.15

Cross multiply

373.15 × V₂ = 250 × 473.15

373.15 × V₂ = 118287.5

Divide both side by 373.15

V₂ = 118287.5 / 373.15

V₂ = 317 mL

Therefore, the final volume of the air sample is 317 mL

you need to give more information

indicate valleys, hills, steepness and gentleness of slopes.

explanation:

contour lines on a map indicate elevation, or depth. numeric notations on contour lines refer to the level of elevation, or height about sea level.