Suppose a wave of visible light of wavelength equal to 555nm was traveling at a velocity of 55.5 cm/s past a point "A". How long would it take for one wavelength of the light to travel past the point "A"?

The answer is ""

Explanation:

In 1 second, cycles take place.

1 wavelength cycle included. Thus, cycles include wavelengths.

wavelengths 1 second until point A

1 wavelength is seconds after A.

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied