For a particular chemical reaction the rate​ (g/hr) at which one of the reactants changes is proportional to the amount of that reactant present. If y represents the amount of that reactant at time​ t, StartFraction dy Over dt EndFraction equals minus0.7y. If there were 70 grams of the reactant when the process started ​(tequals ​0), how many grams will remain after 4 ​hours?

Amount of reactant after four hours = 4,26 grams

Explanation:

Suppose y denotes the amount of reactant at the time (t)

The given function:

Taking integral on both sides

㏑(y) = -0.7t + c¹

At t = 0 ; y (t) = 70

∴

C = 70

As such;

After four hours, the amount of the reactant is:

Amount of reactant after four hours = 4,26 grams

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